(((3^x)-(3^-x))/2)=3

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Solution for (((3^x)-(3^-x))/2)=3 equation: 



(((3^x)-(3^-x))/2)=3

We move all terms to the left:

(((3^x)-(3^-x))/2)-(3)=0

We multiply all the terms by the denominator


((3^x-(3^-x))-3*2)=0



We calculate terms in parentheses: +((3^x-(3^-x))-3*2), so:

(3^x-(3^-x))-3*2

We add all the numbers together, and all the variables

(3^x-(3^-x))-6



We calculate terms in parentheses: +(3^x-(3^-x)), so:

3^x-(3^-x)

We get rid of parentheses

3^x+x-3^

We add all the numbers together, and all the variables

x+3^x

Back to the equation:

+(x+3^x)



We get rid of parentheses

x+3^x-6

Back to the equation:

+(x+3^x-6)



We get rid of parentheses

x+3^x-6=0

We move all terms containing x to the left, all other terms to the right

x+3^x=6

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